10133526643141 has 4 divisors (see below), whose sum is σ = 11054756337984. Its totient is φ = 9212296948300.

The previous prime is 10133526643111. The next prime is 10133526643171. The reversal of 10133526643141 is 14134662533101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10133526643111) and next prime (10133526643171).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10133526643141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10133526643094 and 10133526643103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10133526643111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 460614847405 + ... + 460614847426.

It is an arithmetic number, because the mean of its divisors is an integer number (2763689084496).

Almost surely, 2^{10133526643141} is an apocalyptic number.

10133526643141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10133526643141 is a deficient number, since it is larger than the sum of its proper divisors (921229694843).

10133526643141 is an equidigital number, since it uses as much as digits as its factorization.

10133526643141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 921229694842.

The product of its (nonzero) digits is 155520, while the sum is 40.

The spelling of 10133526643141 in words is "ten trillion, one hundred thirty-three billion, five hundred twenty-six million, six hundred forty-three thousand, one hundred forty-one".