Base | Representation |
---|---|
bin | 101111001100010010… |
… | …1000111000101110011 |
3 | 100200120211211100200002 |
4 | 1132120211013011303 |
5 | 3130023043104021 |
6 | 114320140020215 |
7 | 10215254514221 |
oct | 1363045070563 |
9 | 320524740602 |
10 | 101344113011 |
11 | 39a861230a9 |
12 | 17783b3166b |
13 | 973112139b |
14 | 4c95785b11 |
15 | 298224050b |
hex | 1798947173 |
101344113011 has 4 divisors (see below), whose sum is σ = 102482811000. Its totient is φ = 100205415024.
The previous prime is 101344112897. The next prime is 101344113049. The reversal of 101344113011 is 110311443101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101344113011 is a prime.
It is a super-2 number, since 2×1013441130112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101344110011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 569348861 + ... + 569349038.
It is an arithmetic number, because the mean of its divisors is an integer number (25620702750).
Almost surely, 2101344113011 is an apocalyptic number.
101344113011 is a deficient number, since it is larger than the sum of its proper divisors (1138697989).
101344113011 is an equidigital number, since it uses as much as digits as its factorization.
101344113011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1138697988.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 101344113011 its reverse (110311443101), we get a palindrome (211655556112).
The spelling of 101344113011 in words is "one hundred one billion, three hundred forty-four million, one hundred thirteen thousand, eleven".
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