Search a number
-
+
101344113049 is a prime number
BaseRepresentation
bin101111001100010010…
…1000111000110011001
3100200120211211100201111
41132120211013012121
53130023043104144
6114320140020321
710215254514304
oct1363045070631
9320524740644
10101344113049
1139a86123133
1217783b316a1
1397311213ca
144c95785b3b
152982240534
hex1798947199

101344113049 has 2 divisors, whose sum is σ = 101344113050. Its totient is φ = 101344113048.

The previous prime is 101344112897. The next prime is 101344113067. The reversal of 101344113049 is 940311443101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98307331600 + 3036781449 = 313540^2 + 55107^2 .

It is an emirp because it is prime and its reverse (940311443101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101344113049 - 233 = 92754178457 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101344113049.

It is not a weakly prime, because it can be changed into another prime (101344143049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50672056524 + 50672056525.

It is an arithmetic number, because the mean of its divisors is an integer number (50672056525).

Almost surely, 2101344113049 is an apocalyptic number.

It is an amenable number.

101344113049 is a deficient number, since it is larger than the sum of its proper divisors (1).

101344113049 is an equidigital number, since it uses as much as digits as its factorization.

101344113049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The spelling of 101344113049 in words is "one hundred one billion, three hundred forty-four million, one hundred thirteen thousand, forty-nine".