Base | Representation |
---|---|
bin | 101111001100010100… |
… | …1010000100000011011 |
3 | 100200120220212120221200 |
4 | 1132120221100200123 |
5 | 3130023332401110 |
6 | 114320215205243 |
7 | 10215266662563 |
oct | 1363051204033 |
9 | 320526776850 |
10 | 101345200155 |
11 | 39a867a5971 |
12 | 17784376823 |
13 | 9731412174 |
14 | 4c95989da3 |
15 | 29823a76c0 |
hex | 1798a5081b |
101345200155 has 24 divisors (see below), whose sum is σ = 181331629440. Its totient is φ = 52307199360.
The previous prime is 101345200147. The next prime is 101345200207. The reversal of 101345200155 is 551002543101.
101345200155 is a `hidden beast` number, since 1 + 0 + 134 + 520 + 0 + 1 + 5 + 5 = 666.
It is not a de Polignac number, because 101345200155 - 23 = 101345200147 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36323050 + ... + 36325839.
It is an arithmetic number, because the mean of its divisors is an integer number (7555484560).
Almost surely, 2101345200155 is an apocalyptic number.
101345200155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
101345200155 is a deficient number, since it is larger than the sum of its proper divisors (79986429285).
101345200155 is a wasteful number, since it uses less digits than its factorization.
101345200155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72648931 (or 72648928 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 101345200155 its reverse (551002543101), we get a palindrome (652347743256).
The spelling of 101345200155 in words is "one hundred one billion, three hundred forty-five million, two hundred thousand, one hundred fifty-five".
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