1013640252301 has 4 divisors (see below), whose sum is σ = 1013650965472. Its totient is φ = 1013629539132.

The previous prime is 1013640252293. The next prime is 1013640252319. The reversal of 1013640252301 is 1032520463101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1013640252301 - 2³ = 1013640252293 is a prime.

It is a super-2 number, since 2×1013640252301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1013640252301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1013640255301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5213385 + ... + 5404318.

It is an arithmetic number, because the mean of its divisors is an integer number (253412741368).

Almost surely, 2^{1013640252301} is an apocalyptic number.

It is an amenable number.

1013640252301 is a deficient number, since it is larger than the sum of its proper divisors (10713171).

1013640252301 is an equidigital number, since it uses as much as digits as its factorization.

1013640252301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10713170.

The product of its (nonzero) digits is 4320, while the sum is 28.

The spelling of 1013640252301 in words is "one trillion, thirteen billion, six hundred forty million, two hundred fifty-two thousand, three hundred one".