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10140041311 = 47832120017
BaseRepresentation
bin10010111000110010…
…01100000001011111
3222011200021110200121
421130121030001133
5131231322310221
64354104135411
7506164633441
oct113431140137
928150243617
1010140041311
114333875134
121b6ba67567
13c57a1055a
146c29b8491
153e5321a41
hex25c64c05f

10140041311 has 4 divisors (see below), whose sum is σ = 10142166112. Its totient is φ = 10137916512.

The previous prime is 10140041297. The next prime is 10140041347. The reversal of 10140041311 is 11314004101.

10140041311 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10140041311 - 217 = 10139910239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10140041111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1055226 + ... + 1064791.

It is an arithmetic number, because the mean of its divisors is an integer number (2535541528).

Almost surely, 210140041311 is an apocalyptic number.

10140041311 is a deficient number, since it is larger than the sum of its proper divisors (2124801).

10140041311 is an equidigital number, since it uses as much as digits as its factorization.

10140041311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2124800.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 10140041311 its reverse (11314004101), we get a palindrome (21454045412).

The spelling of 10140041311 in words is "ten billion, one hundred forty million, forty-one thousand, three hundred eleven".

Divisors: 1 4783 2120017 10140041311