101404113112033 has 4 divisors (see below), whose sum is σ = 103877384163588. Its totient is φ = 98930842060480.

The previous prime is 101404113111997. The next prime is 101404113112063. The reversal of 101404113112033 is 330211311404101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40815589909264 + 60588523202769 = 6388708^2 + 7783863^2 .

It is a cyclic number.

It is not a de Polignac number, because 101404113112033 - 2²¹ = 101404111014881 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101404113111989 and 101404113112007.

It is not an unprimeable number, because it can be changed into a prime (101404113112063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1236635525716 + ... + 1236635525797.

It is an arithmetic number, because the mean of its divisors is an integer number (25969346040897).

Almost surely, 2^{101404113112033} is an apocalyptic number.

It is an amenable number.

101404113112033 is a deficient number, since it is larger than the sum of its proper divisors (2473271051555).

101404113112033 is an equidigital number, since it uses as much as digits as its factorization.

101404113112033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2473271051554.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 101404113112033 its reverse (330211311404101), we get a palindrome (431615424516134).

The spelling of 101404113112033 in words is "one hundred one trillion, four hundred four billion, one hundred thirteen million, one hundred twelve thousand, thirty-three".