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101421300103 = 372741116219
BaseRepresentation
bin101111001110100101…
…1100011100110000111
3100200210020001212110021
41132131023203212013
53130202323100403
6114331534240011
710220212553404
oct1363513434607
9320706055407
10101421300103
113a015752992
12177a5956007
139744108316
144ca1b192ab
152988dda8bd
hex179d2e3987

101421300103 has 4 divisors (see below), whose sum is σ = 104162416360. Its totient is φ = 98680183848.

The previous prime is 101421300073. The next prime is 101421300107. The reversal of 101421300103 is 301003124101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101421300103 is a prime.

It is a super-3 number, since 3×1014213001033 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101421300107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1370558073 + ... + 1370558146.

It is an arithmetic number, because the mean of its divisors is an integer number (26040604090).

Almost surely, 2101421300103 is an apocalyptic number.

101421300103 is a deficient number, since it is larger than the sum of its proper divisors (2741116257).

101421300103 is an equidigital number, since it uses as much as digits as its factorization.

101421300103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2741116256.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 101421300103 its reverse (301003124101), we get a palindrome (402424424204).

The spelling of 101421300103 in words is "one hundred one billion, four hundred twenty-one million, three hundred thousand, one hundred three".

Divisors: 1 37 2741116219 101421300103