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10142143113 = 34771930093
BaseRepresentation
bin10010111001000010…
…01101001010001001
3222011211020020211010
421130201031022021
5131232342034423
64354221154133
7506221536234
oct113441151211
928154206733
1010142143113
114334a80263
121b706bb949
13c5829811b
146c2da441b
153e55d9693
hex25c84d289

10142143113 has 8 divisors (see below), whose sum is σ = 13810578048. Its totient is φ = 6617568464.

The previous prime is 10142143111. The next prime is 10142143153. The reversal of 10142143113 is 31134124101.

10142143113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10142143113 - 21 = 10142143111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10142143113.

It is not an unprimeable number, because it can be changed into a prime (10142143111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35964906 + ... + 35965187.

It is an arithmetic number, because the mean of its divisors is an integer number (1726322256).

Almost surely, 210142143113 is an apocalyptic number.

It is an amenable number.

10142143113 is a deficient number, since it is larger than the sum of its proper divisors (3668434935).

10142143113 is an equidigital number, since it uses as much as digits as its factorization.

10142143113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71930143.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 10142143113 its reverse (31134124101), we get a palindrome (41276267214).

The spelling of 10142143113 in words is "ten billion, one hundred forty-two million, one hundred forty-three thousand, one hundred thirteen".

Divisors: 1 3 47 141 71930093 215790279 3380714371 10142143113