10143113012121 has 4 divisors (see below), whose sum is σ = 13524150682832. Its totient is φ = 6762075341412.

The previous prime is 10143113012113. The next prime is 10143113012159. The reversal of 10143113012121 is 12121031134101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10143113012121 - 2³ = 10143113012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10143113012161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1690518835351 + ... + 1690518835356.

It is an arithmetic number, because the mean of its divisors is an integer number (3381037670708).

Almost surely, 2^{10143113012121} is an apocalyptic number.

It is an amenable number.

10143113012121 is a deficient number, since it is larger than the sum of its proper divisors (3381037670711).

10143113012121 is an equidigital number, since it uses as much as digits as its factorization.

10143113012121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3381037670710.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 10143113012121 its reverse (12121031134101), we get a palindrome (22264144146222).

The spelling of 10143113012121 in words is "ten trillion, one hundred forty-three billion, one hundred thirteen million, twelve thousand, one hundred twenty-one".