10143134011 has 4 divisors (see below), whose sum is σ = 10334513952. Its totient is φ = 9951754072.

The previous prime is 10143134003. The next prime is 10143134101. The reversal of 10143134011 is 11043134101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11043134101 = 701 ⋅15753401.

It is a cyclic number.

It is not a de Polignac number, because 10143134011 - 2³ = 10143134003 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10143134011.

It is not an unprimeable number, because it can be changed into a prime (10143135011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95689891 + ... + 95689996.

It is an arithmetic number, because the mean of its divisors is an integer number (2583628488).

Almost surely, 2^10143134011 is an apocalyptic number.

10143134011 is a deficient number, since it is larger than the sum of its proper divisors (191379941).

10143134011 is an equidigital number, since it uses as much as digits as its factorization.

10143134011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191379940.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10143134011 its reverse (11043134101), we get a palindrome (21186268112).

The spelling of 10143134011 in words is "ten billion, one hundred forty-three million, one hundred thirty-four thousand, eleven".