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101431426433 = 113118967503
BaseRepresentation
bin101111001110111001…
…0001011110110000001
3100200210221010100011112
41132131302023312001
53130212421121213
6114332535253105
710220364620261
oct1363562136601
9320727110145
10101431426433
113a020439a57
12177a921a195
13974624252c
144ca31d37a1
152989c3aea8
hex179dc8bd81

101431426433 has 4 divisors (see below), whose sum is σ = 101440405248. Its totient is φ = 101422447620.

The previous prime is 101431426399. The next prime is 101431426441. The reversal of 101431426433 is 334624134101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101431426433 - 220 = 101430377857 is a prime.

It is a super-2 number, since 2×1014314264332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 101431426433.

It is not an unprimeable number, because it can be changed into a prime (101431426463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4472441 + ... + 4495062.

It is an arithmetic number, because the mean of its divisors is an integer number (25360101312).

Almost surely, 2101431426433 is an apocalyptic number.

It is an amenable number.

101431426433 is a deficient number, since it is larger than the sum of its proper divisors (8978815).

101431426433 is an equidigital number, since it uses as much as digits as its factorization.

101431426433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8978814.

The product of its (nonzero) digits is 20736, while the sum is 32.

The spelling of 101431426433 in words is "one hundred one billion, four hundred thirty-one million, four hundred twenty-six thousand, four hundred thirty-three".

Divisors: 1 11311 8967503 101431426433