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10143354313 = 80691257077
BaseRepresentation
bin10010111001001011…
…10100110111001001
3222011220111210021101
421130211310313021
5131233144314223
64354303141401
7506235042361
oct113445646711
928156453241
1010143354313
114335728254
121b70ba4861
13c58600501
146c31db9a1
153e57784ad
hex25c974dc9

10143354313 has 4 divisors (see below), whose sum is σ = 10144619460. Its totient is φ = 10142089168.

The previous prime is 10143354289. The next prime is 10143354337. The reversal of 10143354313 is 31345334101.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (10143354289) and next prime (10143354337).

It can be written as a sum of positive squares in 2 ways, for example, as 164942649 + 9978411664 = 12843^2 + 99892^2 .

It is a cyclic number.

It is not a de Polignac number, because 10143354313 - 229 = 9606483401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10143354343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620470 + ... + 636607.

It is an arithmetic number, because the mean of its divisors is an integer number (2536154865).

Almost surely, 210143354313 is an apocalyptic number.

It is an amenable number.

10143354313 is a deficient number, since it is larger than the sum of its proper divisors (1265147).

10143354313 is an equidigital number, since it uses as much as digits as its factorization.

10143354313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1265146.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 10143354313 its reverse (31345334101), we get a palindrome (41488688414).

The spelling of 10143354313 in words is "ten billion, one hundred forty-three million, three hundred fifty-four thousand, three hundred thirteen".

Divisors: 1 8069 1257077 10143354313