Base | Representation |
---|---|
bin | 10010111001001100… |
… | …01101010001101001 |
3 | 222011220200212110002 |
4 | 21130212031101221 |
5 | 131233211014223 |
6 | 4354305232345 |
7 | 506235640046 |
oct | 113446152151 |
9 | 28156625402 |
10 | 10143454313 |
11 | 43357963a3 |
12 | 1b710326b5 |
13 | c58636b95 |
14 | 6c32261cd |
15 | 3e5797e28 |
hex | 25c98d469 |
10143454313 has 4 divisors (see below), whose sum is σ = 10223324160. Its totient is φ = 10063584468.
The previous prime is 10143454301. The next prime is 10143454331. The reversal of 10143454313 is 31345434101.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31345434101 = 521 ⋅60163981.
It is a cyclic number.
It is not a de Polignac number, because 10143454313 - 24 = 10143454297 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10143454813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39934733 + ... + 39934986.
It is an arithmetic number, because the mean of its divisors is an integer number (2555831040).
Almost surely, 210143454313 is an apocalyptic number.
It is an amenable number.
10143454313 is a deficient number, since it is larger than the sum of its proper divisors (79869847).
10143454313 is an equidigital number, since it uses as much as digits as its factorization.
10143454313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79869846.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 10143454313 its reverse (31345434101), we get a palindrome (41488888414).
The spelling of 10143454313 in words is "ten billion, one hundred forty-three million, four hundred fifty-four thousand, three hundred thirteen".
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