101435113541231 has 4 divisors (see below), whose sum is σ = 101435133712872. Its totient is φ = 101435093369592.

The previous prime is 101435113541227. The next prime is 101435113541291. The reversal of 101435113541231 is 132145311534101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101435113541231 - 2² = 101435113541227 is a prime.

It is a super-2 number, since 2×101435113541231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101435113541191 and 101435113541200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101435113541291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4237016 + ... + 14860098.

It is an arithmetic number, because the mean of its divisors is an integer number (25358783428218).

Almost surely, 2^{101435113541231} is an apocalyptic number.

101435113541231 is a deficient number, since it is larger than the sum of its proper divisors (20171641).

101435113541231 is an equidigital number, since it uses as much as digits as its factorization.

101435113541231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20171640.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 101435113541231 in words is "one hundred one trillion, four hundred thirty-five billion, one hundred thirteen million, five hundred forty-one thousand, two hundred thirty-one".