101443121141 has 4 divisors (see below), whose sum is σ = 106782232800. Its totient is φ = 96104009484.

The previous prime is 101443121137. The next prime is 101443121161. The reversal of 101443121141 is 141121344101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101443121141 - 2² = 101443121137 is a prime.

It is a super-2 number, since 2×101443121141² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101443121161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2669555801 + ... + 2669555838.

It is an arithmetic number, because the mean of its divisors is an integer number (26695558200).

Almost surely, 2^101443121141 is an apocalyptic number.

It is an amenable number.

101443121141 is a deficient number, since it is larger than the sum of its proper divisors (5339111659).

101443121141 is an equidigital number, since it uses as much as digits as its factorization.

101443121141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5339111658.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 101443121141 its reverse (141121344101), we get a palindrome (242564465242).

The spelling of 101443121141 in words is "one hundred one billion, four hundred forty-three million, one hundred twenty-one thousand, one hundred forty-one".