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10144410013 = 13972981367
BaseRepresentation
bin10010111001010011…
…10110100110011101
3222011222111102102101
421130221312212131
5131233432110023
64354341525101
7506250030253
oct113451664635
928158442371
1010144410013
114336289431
121b71413791
13c588acb9a
146c33d45d3
153e58d61ad
hex25ca7699d

10144410013 has 4 divisors (see below), whose sum is σ = 10217391520. Its totient is φ = 10071428508.

The previous prime is 10144410007. The next prime is 10144410043. The reversal of 10144410013 is 31001444101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10144410013 - 29 = 10144409501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10144410043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36490545 + ... + 36490822.

It is an arithmetic number, because the mean of its divisors is an integer number (2554347880).

Almost surely, 210144410013 is an apocalyptic number.

It is an amenable number.

10144410013 is a deficient number, since it is larger than the sum of its proper divisors (72981507).

10144410013 is an equidigital number, since it uses as much as digits as its factorization.

10144410013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72981506.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 10144410013 its reverse (31001444101), we get a palindrome (41145854114).

The spelling of 10144410013 in words is "ten billion, one hundred forty-four million, four hundred ten thousand, thirteen".

Divisors: 1 139 72981367 10144410013