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10145412551 = 28136104671
BaseRepresentation
bin10010111001011011…
…01011010111000111
3222012001101100122102
421130231223113013
5131234211200201
64354415222315
7506261404151
oct113455532707
928161340572
1010145412551
11433690367a
121b7181799b
13c58b712c1
146c35b5ad1
153e5a3326b
hex25cb6b5c7

10145412551 has 4 divisors (see below), whose sum is σ = 10181517504. Its totient is φ = 10109307600.

The previous prime is 10145412523. The next prime is 10145412559. The reversal of 10145412551 is 15521454101.

10145412551 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10145412551 - 226 = 10078303687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10145412559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18052055 + ... + 18052616.

It is an arithmetic number, because the mean of its divisors is an integer number (2545379376).

Almost surely, 210145412551 is an apocalyptic number.

10145412551 is a deficient number, since it is larger than the sum of its proper divisors (36104953).

10145412551 is an equidigital number, since it uses as much as digits as its factorization.

10145412551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36104952.

The product of its (nonzero) digits is 4000, while the sum is 29.

Adding to 10145412551 its reverse (15521454101), we get a palindrome (25666866652).

The spelling of 10145412551 in words is "ten billion, one hundred forty-five million, four hundred twelve thousand, five hundred fifty-one".

Divisors: 1 281 36104671 10145412551