1016421213 has 4 divisors (see below), whose sum is σ = 1355228288. Its totient is φ = 677614140.

The previous prime is 1016421187. The next prime is 1016421233. The reversal of 1016421213 is 3121246101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3121246101 = 3 ⋅1040415367.

It is not a de Polignac number, because 1016421213 - 2⁵ = 1016421181 is a prime.

It is a super-2 number, since 2×1016421213² = 2066224164472782738, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1016421213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1016421233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169403533 + ... + 169403538.

It is an arithmetic number, because the mean of its divisors is an integer number (338807072).

Almost surely, 2^1016421213 is an apocalyptic number.

It is an amenable number.

1016421213 is a deficient number, since it is larger than the sum of its proper divisors (338807075).

1016421213 is an equidigital number, since it uses as much as digits as its factorization.

1016421213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 338807074.

The product of its (nonzero) digits is 288, while the sum is 21.

The square root of 1016421213 is about 31881.3615298971. The cubic root of 1016421213 is about 1005.4440462443. Note that the first 3 decimals are identical.

Adding to 1016421213 its reverse (3121246101), we get a palindrome (4137667314).

The spelling of 1016421213 in words is "one billion, sixteen million, four hundred twenty-one thousand, two hundred thirteen".