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10201202113 = 71143678903
BaseRepresentation
bin10011000000000100…
…11111110111000001
3222022221100202112111
421200002133313001
5131343001431423
64404131055321
7510536534014
oct114002376701
928287322474
1010201202113
114365349153
121b88441541
13c675a598b
146cab7937b
153ea8a360d
hex26009fdc1

10201202113 has 4 divisors (see below), whose sum is σ = 10344881088. Its totient is φ = 10057523140.

The previous prime is 10201202093. The next prime is 10201202171. The reversal of 10201202113 is 31120210201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10201202113 - 221 = 10199104961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10201202093 and 10201202102.

It is not an unprimeable number, because it can be changed into a prime (10201202513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71839381 + ... + 71839522.

It is an arithmetic number, because the mean of its divisors is an integer number (2586220272).

Almost surely, 210201202113 is an apocalyptic number.

It is an amenable number.

10201202113 is a deficient number, since it is larger than the sum of its proper divisors (143678975).

10201202113 is an equidigital number, since it uses as much as digits as its factorization.

10201202113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143678974.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10201202113 its reverse (31120210201), we get a palindrome (41321412314).

The spelling of 10201202113 in words is "ten billion, two hundred one million, two hundred two thousand, one hundred thirteen".

Divisors: 1 71 143678903 10201202113