Base | Representation |
---|---|
bin | 11101101100101101010… |
… | …00011110010011011001 |
3 | 10121112220211102121100020 |
4 | 32312112220132103121 |
5 | 113204322204111213 |
6 | 2100440415301053 |
7 | 133503213432021 |
oct | 16662650362331 |
9 | 3545824377306 |
10 | 1020434441433 |
11 | 363844704220 |
12 | 14592551a789 |
13 | 752c39834c4 |
14 | 375642daa81 |
15 | 1b8256ea923 |
hex | ed96a1e4d9 |
1020434441433 has 64 divisors (see below), whose sum is σ = 1533201868800. Its totient is φ = 598322880000.
The previous prime is 1020434441393. The next prime is 1020434441471. The reversal of 1020434441433 is 3341444340201.
It is not a de Polignac number, because 1020434441433 - 213 = 1020434433241 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 1020434441394 and 1020434441403.
It is not an unprimeable number, because it can be changed into a prime (1020434441483) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 126459523 + ... + 126467591.
It is an arithmetic number, because the mean of its divisors is an integer number (23956279200).
Almost surely, 21020434441433 is an apocalyptic number.
It is an amenable number.
1020434441433 is a deficient number, since it is larger than the sum of its proper divisors (512767427367).
1020434441433 is a wasteful number, since it uses less digits than its factorization.
1020434441433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8894.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 1020434441433 its reverse (3341444340201), we get a palindrome (4361878781634).
The spelling of 1020434441433 in words is "one trillion, twenty billion, four hundred thirty-four million, four hundred forty-one thousand, four hundred thirty-three".
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