10210004113 has 4 divisors (see below), whose sum is σ = 10283457520. Its totient is φ = 10136550708.

The previous prime is 10210004017. The next prime is 10210004149. The reversal of 10210004113 is 31140001201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31140001201 = 877 ⋅35507413.

It is a cyclic number.

It is not a de Polignac number, because 10210004113 - 2²⁵ = 10176449681 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10210004093 and 10210004102.

It is not an unprimeable number, because it can be changed into a prime (10210004173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36726495 + ... + 36726772.

It is an arithmetic number, because the mean of its divisors is an integer number (2570864380).

Almost surely, 2^10210004113 is an apocalyptic number.

It is an amenable number.

10210004113 is a deficient number, since it is larger than the sum of its proper divisors (73453407).

10210004113 is an equidigital number, since it uses as much as digits as its factorization.

10210004113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73453406.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10210004113 its reverse (31140001201), we get a palindrome (41350005314).

The spelling of 10210004113 in words is "ten billion, two hundred ten million, four thousand, one hundred thirteen".