10210331113 has 4 divisors (see below), whose sum is σ = 10232384128. Its totient is φ = 10188278100.

The previous prime is 10210331083. The next prime is 10210331149. The reversal of 10210331113 is 31113301201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31113301201 = 157 ⋅198173893.

It is a cyclic number.

It is not a de Polignac number, because 10210331113 - 2⁹ = 10210330601 is a prime.

It is a super-2 number, since 2×10210331113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10210331413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11025813 + ... + 11026738.

It is an arithmetic number, because the mean of its divisors is an integer number (2558096032).

Almost surely, 2^10210331113 is an apocalyptic number.

It is an amenable number.

10210331113 is a deficient number, since it is larger than the sum of its proper divisors (22053015).

10210331113 is an equidigital number, since it uses as much as digits as its factorization.

10210331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22053014.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10210331113 its reverse (31113301201), we get a palindrome (41323632314).

The spelling of 10210331113 in words is "ten billion, two hundred ten million, three hundred thirty-one thousand, one hundred thirteen".