Base | Representation |
---|---|
bin | 11101111000001001111100… |
… | …101010110001111111011111 |
3 | 122020020221100200110022020220 |
4 | 131320021330222301333133 |
5 | 114210343423141342143 |
6 | 1143245220512412423 |
7 | 36451335003666123 |
oct | 3570117452617737 |
9 | 566227320408226 |
10 | 131402321043423 |
11 | 38961458639821 |
12 | 128a2797547113 |
13 | 5842254cc1521 |
14 | 2463c98b53583 |
15 | 102d121384d83 |
hex | 77827cab1fdf |
131402321043423 has 64 divisors (see below), whose sum is σ = 182262651863040. Its totient is φ = 84161574476928.
The previous prime is 131402321043403. The next prime is 131402321043443. The reversal of 131402321043423 is 324340123204131.
It is an interprime number because it is at equal distance from previous prime (131402321043403) and next prime (131402321043443).
It is not a de Polignac number, because 131402321043423 - 214 = 131402321027039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131402321043403) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 929204640 + ... + 929346042.
It is an arithmetic number, because the mean of its divisors is an integer number (2847853935360).
Almost surely, 2131402321043423 is an apocalyptic number.
131402321043423 is a deficient number, since it is larger than the sum of its proper divisors (50860330819617).
131402321043423 is a wasteful number, since it uses less digits than its factorization.
131402321043423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142148.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 131402321043423 its reverse (324340123204131), we get a palindrome (455742444247554).
The spelling of 131402321043423 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred twenty-one million, forty-three thousand, four hundred twenty-three".
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