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10211121113100 = 22352378932093221
BaseRepresentation
bin1001010010010111011000…
…1111110010100000001100
31100011011200120212000111120
42110211312033302200030
52314244334001104400
633414531351120540
72102505046242465
oct224456617624014
940134616760446
1010211121113100
11328756a735086
12118ab97973150
13590b9b4c879b
14274314209d6c
1512a9348cbca0
hex949763f280c

10211121113100 has 288 divisors, whose sum is σ = 30702688027200. Its totient is φ = 2617974374400.

The previous prime is 10211121113093. The next prime is 10211121113107. The reversal of 10211121113100 is 131112111201.

It is an interprime number because it is at equal distance from previous prime (10211121113093) and next prime (10211121113107).

It is a super-3 number, since 3×102111211131003 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 10211121113100.

It is not an unprimeable number, because it can be changed into a prime (10211121113107) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3170169490 + ... + 3170172710.

It is an arithmetic number, because the mean of its divisors is an integer number (106606555650).

Almost surely, 210211121113100 is an apocalyptic number.

10211121113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10211121113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15351344013600).

10211121113100 is an abundant number, since it is smaller than the sum of its proper divisors (20491566914100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10211121113100 is a wasteful number, since it uses less digits than its factorization.

10211121113100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6573 (or 6566 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 10211121113100 its reverse (131112111201), we get a palindrome (10342233224301).

The spelling of 10211121113100 in words is "ten trillion, two hundred eleven billion, one hundred twenty-one million, one hundred thirteen thousand, one hundred".