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1021131001303 = 7577252817777
BaseRepresentation
bin11101101110000000010…
…01101000110111010111
310121121201101010111211221
432313000021220313113
5113212234014020203
62101033501111211
7133526402204560
oct16670011506727
93547641114757
101021131001303
11364071913a36
12145a9a858507
13753a5089aca
14375cca1b167
151b86693dabd
hexedc0268dd7

1021131001303 has 8 divisors (see below), whose sum is σ = 1169029405472. Its totient is φ = 873738233856.

The previous prime is 1021131001133. The next prime is 1021131001321. The reversal of 1021131001303 is 3031001311201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1021131001303 - 233 = 1012541066711 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1021131101303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126404850 + ... + 126412927.

It is an arithmetic number, because the mean of its divisors is an integer number (146128675684).

Almost surely, 21021131001303 is an apocalyptic number.

1021131001303 is a deficient number, since it is larger than the sum of its proper divisors (147898404169).

1021131001303 is an equidigital number, since it uses as much as digits as its factorization.

1021131001303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 252818361.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1021131001303 its reverse (3031001311201), we get a palindrome (4052132312504).

The spelling of 1021131001303 in words is "one trillion, twenty-one billion, one hundred thirty-one million, one thousand, three hundred three".

Divisors: 1 7 577 4039 252817777 1769724439 145875857329 1021131001303