1021131300121 has 4 divisors (see below), whose sum is σ = 1021226273332. Its totient is φ = 1021036326912.

The previous prime is 1021131300109. The next prime is 1021131300149. The reversal of 1021131300121 is 1210031311201.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 653696505225 + 367434794896 = 808515^2 + 606164^2 .

It is a cyclic number.

It is not a de Polignac number, because 1021131300121 - 2¹⁵ = 1021131267353 is a prime.

It is a super-2 number, since 2×1021131300121² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1021131300095 and 1021131300104.

It is not an unprimeable number, because it can be changed into a prime (1021131300821) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47470476 + ... + 47491981.

It is an arithmetic number, because the mean of its divisors is an integer number (255306568333).

Almost surely, 2^{1021131300121} is an apocalyptic number.

It is an amenable number.

1021131300121 is a deficient number, since it is larger than the sum of its proper divisors (94973211).

1021131300121 is an equidigital number, since it uses as much as digits as its factorization.

1021131300121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94973210.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1021131300121 its reverse (1210031311201), we get a palindrome (2231162611322).

The spelling of 1021131300121 in words is "one trillion, twenty-one billion, one hundred thirty-one million, three hundred thousand, one hundred twenty-one".