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10211313110114 = 25105656555057
BaseRepresentation
bin1001010010011000000110…
…1100001100110001100010
31100011012011222010110220002
42110212001230030301202
52314300232124010424
633415002410220002
72102512600215524
oct224460154146142
940135158113802
1010211313110114
1132876590512a6
12118b030124602
13590bcc21019c
14274331907a14
1512a9466a4cae
hex94981b0cc62

10211313110114 has 4 divisors (see below), whose sum is σ = 15316969665174. Its totient is φ = 5105656555056.

The previous prime is 10211313110113. The next prime is 10211313110153. The reversal of 10211313110114 is 41101131311201.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 5588103582889 + 4623209527225 = 2363917^2 + 2150165^2 .

It is not an unprimeable number, because it can be changed into a prime (10211313110113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2552828277527 + ... + 2552828277530.

Almost surely, 210211313110114 is an apocalyptic number.

10211313110114 is a deficient number, since it is larger than the sum of its proper divisors (5105656555060).

10211313110114 is an equidigital number, since it uses as much as digits as its factorization.

10211313110114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5105656555059.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 10211313110114 its reverse (41101131311201), we get a palindrome (51312444421315).

The spelling of 10211313110114 in words is "ten trillion, two hundred eleven billion, three hundred thirteen million, one hundred ten thousand, one hundred fourteen".

Divisors: 1 2 5105656555057 10211313110114