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10211313120107 = 114909189101893
BaseRepresentation
bin1001010010011000000110…
…1100001111001101101011
31100011012011222010222121012
42110212001230033031223
52314300232124320412
633415002410334135
72102512600256621
oct224460154171553
940135158128535
1010211313120107
113287659058860
12118b03012a34b
13590bcc2148b8
1427433190b511
1512a9466a7c22
hex94981b0f36b

10211313120107 has 8 divisors (see below), whose sum is σ = 11141883594480. Its totient is φ = 9281120859360.

The previous prime is 10211313120077. The next prime is 10211313120139. The reversal of 10211313120107 is 70102131311201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10211313120107 - 210 = 10211313119083 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10211313120607) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94496948 + ... + 94604945.

It is an arithmetic number, because the mean of its divisors is an integer number (1392735449310).

Almost surely, 210211313120107 is an apocalyptic number.

10211313120107 is a deficient number, since it is larger than the sum of its proper divisors (930570474373).

10211313120107 is a wasteful number, since it uses less digits than its factorization.

10211313120107 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189106813.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 10211313120107 its reverse (70102131311201), we get a palindrome (80313444431308).

The spelling of 10211313120107 in words is "ten trillion, two hundred eleven billion, three hundred thirteen million, one hundred twenty thousand, one hundred seven".

Divisors: 1 11 4909 53999 189101893 2080120823 928301192737 10211313120107