Base | Representation |
---|---|
bin | 1001010010011000000110… |
… | …1100001111001101001101 |
3 | 1100011012011222010222120002 |
4 | 2110212001230033031031 |
5 | 2314300232124320302 |
6 | 33415002410334045 |
7 | 2102512600256546 |
oct | 224460154171515 |
9 | 40135158128502 |
10 | 10211313120077 |
11 | 3287659058833 |
12 | 118b03012a325 |
13 | 590bcc214894 |
14 | 27433190b4cd |
15 | 12a9466a7c02 |
hex | 94981b0f34d |
10211313120077 has 2 divisors, whose sum is σ = 10211313120078. Its totient is φ = 10211313120076.
The previous prime is 10211313120061. The next prime is 10211313120139. The reversal of 10211313120077 is 77002131311201.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9931788372676 + 279524747401 = 3151474^2 + 528701^2 .
It is a cyclic number.
It is not a de Polignac number, because 10211313120077 - 24 = 10211313120061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10211313125077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105656560038 + 5105656560039.
It is an arithmetic number, because the mean of its divisors is an integer number (5105656560039).
Almost surely, 210211313120077 is an apocalyptic number.
It is an amenable number.
10211313120077 is a deficient number, since it is larger than the sum of its proper divisors (1).
10211313120077 is an equidigital number, since it uses as much as digits as its factorization.
10211313120077 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1764, while the sum is 29.
Adding to 10211313120077 its reverse (77002131311201), we get a palindrome (87213444431278).
The spelling of 10211313120077 in words is "ten trillion, two hundred eleven billion, three hundred thirteen million, one hundred twenty thousand, seventy-seven".
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