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102114003151 = 3716316931521
BaseRepresentation
bin101111100011001111…
…0000000100011001111
3100202120111111211101201
41133012132000203033
53133112141100101
6114524401250331
710243323463666
oct1370636004317
9322514454351
10102114003151
113a340768a46
12179599339a7
139824791294
144d29b13ddd
1529c9b1ae01
hex17c67808cf

102114003151 has 8 divisors (see below), whose sum is σ = 105517245104. Its totient is φ = 98744624640.

The previous prime is 102114003143. The next prime is 102114003197. The reversal of 102114003151 is 151300411201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 102114003151 - 23 = 102114003143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102114006151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8459730 + ... + 8471791.

It is an arithmetic number, because the mean of its divisors is an integer number (13189655638).

Almost surely, 2102114003151 is an apocalyptic number.

102114003151 is a deficient number, since it is larger than the sum of its proper divisors (3403241953).

102114003151 is a wasteful number, since it uses less digits than its factorization.

102114003151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16931721.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 102114003151 its reverse (151300411201), we get a palindrome (253414414352).

The spelling of 102114003151 in words is "one hundred two billion, one hundred fourteen million, three thousand, one hundred fifty-one".

Divisors: 1 37 163 6031 16931521 626466277 2759837923 102114003151