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102115152551 = 271376808681
BaseRepresentation
bin101111100011010001…
…0011001001010100111
3100202120120200020002002
41133012202121022213
53133112434340201
6114524442035515
710243336322006
oct1370642311247
9322516606062
10102115152551
113a341383565
121795a1a8b9b
139824aa44b9
144d29d32c3d
1529c9c9676b
hex17c68992a7

102115152551 has 4 divisors (see below), whose sum is σ = 102491961504. Its totient is φ = 101738343600.

The previous prime is 102115152541. The next prime is 102115152571. The reversal of 102115152551 is 155251511201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102115152551 - 210 = 102115151527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102115152541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188404070 + ... + 188404611.

It is an arithmetic number, because the mean of its divisors is an integer number (25622990376).

Almost surely, 2102115152551 is an apocalyptic number.

102115152551 is a deficient number, since it is larger than the sum of its proper divisors (376808953).

102115152551 is an equidigital number, since it uses as much as digits as its factorization.

102115152551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 376808952.

The product of its (nonzero) digits is 2500, while the sum is 29.

Adding to 102115152551 its reverse (155251511201), we get a palindrome (257366663752).

The spelling of 102115152551 in words is "one hundred two billion, one hundred fifteen million, one hundred fifty-two thousand, five hundred fifty-one".

Divisors: 1 271 376808681 102115152551