102121031320133 has 4 divisors (see below), whose sum is σ = 116709750080160. Its totient is φ = 87532312560108.

The previous prime is 102121031320037. The next prime is 102121031320159. The reversal of 102121031320133 is 331023130121201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102121031320133 - 2¹⁴ = 102121031303749 is a prime.

It is a super-2 number, since 2×102121031320133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102121031320099 and 102121031320108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102121031325133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7294359380003 + ... + 7294359380016.

It is an arithmetic number, because the mean of its divisors is an integer number (29177437520040).

Almost surely, 2^{102121031320133} is an apocalyptic number.

It is an amenable number.

102121031320133 is a deficient number, since it is larger than the sum of its proper divisors (14588718760027).

102121031320133 is an equidigital number, since it uses as much as digits as its factorization.

102121031320133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14588718760026.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 102121031320133 its reverse (331023130121201), we get a palindrome (433144161441334).

The spelling of 102121031320133 in words is "one hundred two trillion, one hundred twenty-one billion, thirty-one million, three hundred twenty thousand, one hundred thirty-three".