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10212201203 = 101208348541
BaseRepresentation
bin10011000001011000…
…11101001011110011
3222100201001120110012
421200230131023303
5131403310414303
64405202525135
7511032164231
oct114054351363
928321046405
1010212201203
114370580a06
121b900667ab
13c69957209
146cc3dd951
153eb8275d8
hex260b1d2f3

10212201203 has 8 divisors (see below), whose sum is σ = 10318475856. Its totient is φ = 10106028000.

The previous prime is 10212201199. The next prime is 10212201211. The reversal of 10212201203 is 30210221201.

It is a happy number.

10212201203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10212201203 - 22 = 10212201199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10212201283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 186113 + ... + 234653.

It is an arithmetic number, because the mean of its divisors is an integer number (1289809482).

Almost surely, 210212201203 is an apocalyptic number.

10212201203 is a deficient number, since it is larger than the sum of its proper divisors (106274653).

10212201203 is a wasteful number, since it uses less digits than its factorization.

10212201203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50725.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 10212201203 its reverse (30210221201), we get a palindrome (40422422404).

The spelling of 10212201203 in words is "ten billion, two hundred twelve million, two hundred one thousand, two hundred three".

Divisors: 1 101 2083 48541 210383 4902641 101110903 10212201203