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10212220133 = 23444009571
BaseRepresentation
bin10011000001011001…
…00001110011100101
3222100201002112102022
421200230201303211
5131403312021013
64405203152525
7511032303353
oct114054416345
928321075368
1010212220133
114370594155
121b90075745
13c69962a0b
146cc4067d3
153eb82d008
hex260b21ce5

10212220133 has 4 divisors (see below), whose sum is σ = 10656229728. Its totient is φ = 9768210540.

The previous prime is 10212220097. The next prime is 10212220141. The reversal of 10212220133 is 33102221201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10212220133 - 26 = 10212220069 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10212220163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222004763 + ... + 222004808.

It is an arithmetic number, because the mean of its divisors is an integer number (2664057432).

Almost surely, 210212220133 is an apocalyptic number.

It is an amenable number.

10212220133 is a deficient number, since it is larger than the sum of its proper divisors (444009595).

10212220133 is an equidigital number, since it uses as much as digits as its factorization.

10212220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444009594.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10212220133 its reverse (33102221201), we get a palindrome (43314441334).

The spelling of 10212220133 in words is "ten billion, two hundred twelve million, two hundred twenty thousand, one hundred thirty-three".

Divisors: 1 23 444009571 10212220133