Base | Representation |
---|---|
bin | 1001010010011011100001… |
… | …1010101001100101011111 |
3 | 1100011021112221210010211122 |
4 | 2110212320122221211133 |
5 | 2314304122200201130 |
6 | 33415233445241155 |
7 | 2102544416303066 |
oct | 224467032514537 |
9 | 40137487703748 |
10 | 10212231256415 |
11 | 3287a8a3481a1 |
12 | 118b2477031bb |
13 | 5910174bb316 |
14 | 2743bb8291dd |
15 | 12a99c0b82e5 |
hex | 949b86a995f |
10212231256415 has 8 divisors (see below), whose sum is σ = 12422549802768. Its totient is φ = 8057870141760.
The previous prime is 10212231256391. The next prime is 10212231256427. The reversal of 10212231256415 is 51465213221201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10212231256415 - 214 = 10212231240031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13989357521 + ... + 13989358250.
It is an arithmetic number, because the mean of its divisors is an integer number (1552818725346).
Almost surely, 210212231256415 is an apocalyptic number.
10212231256415 is a deficient number, since it is larger than the sum of its proper divisors (2210318546353).
10212231256415 is an equidigital number, since it uses as much as digits as its factorization.
10212231256415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27978715849.
The product of its (nonzero) digits is 28800, while the sum is 35.
Adding to 10212231256415 its reverse (51465213221201), we get a palindrome (61677444477616).
The spelling of 10212231256415 in words is "ten trillion, two hundred twelve billion, two hundred thirty-one million, two hundred fifty-six thousand, four hundred fifteen".
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