Base | Representation |
---|---|
bin | 10011000001011001… |
… | …01110100100110001 |
3 | 222100201012012011100 |
4 | 21200230232210301 |
5 | 131403320204213 |
6 | 4405204235013 |
7 | 511032612006 |
oct | 114054564461 |
9 | 28321165140 |
10 | 10212272433 |
11 | 437061a480 |
12 | 1b9009ba69 |
13 | c6998076c |
14 | 6cc41b8ad |
15 | 3eb83d773 |
hex | 260b2e931 |
10212272433 has 48 divisors (see below), whose sum is σ = 16845484032. Its totient is φ = 5905116000.
The previous prime is 10212272429. The next prime is 10212272467. The reversal of 10212272433 is 33427221201.
10212272433 is a `hidden beast` number, since 1 + 0 + 2 + 1 + 227 + 2 + 433 = 666.
It is not a de Polignac number, because 10212272433 - 22 = 10212272429 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10212272397 and 10212272406.
It is not an unprimeable number, because it can be changed into a prime (10212272033) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 194466 + ... + 241332.
It is an arithmetic number, because the mean of its divisors is an integer number (350947584).
Almost surely, 210212272433 is an apocalyptic number.
It is an amenable number.
10212272433 is a deficient number, since it is larger than the sum of its proper divisors (6633211599).
10212272433 is a wasteful number, since it uses less digits than its factorization.
10212272433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46986 (or 46983 counting only the distinct ones).
The product of its (nonzero) digits is 4032, while the sum is 27.
Adding to 10212272433 its reverse (33427221201), we get a palindrome (43639493634).
The spelling of 10212272433 in words is "ten billion, two hundred twelve million, two hundred seventy-two thousand, four hundred thirty-three".
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