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1021241141335 = 5204248228267
BaseRepresentation
bin11101101110001101011…
…01110010100001010111
310121122000001101012120101
432313012231302201113
5113213000213010320
62101052433514531
7133532210321542
oct16670655624127
93548001335511
101021241141335
11364119000858
12145b0b712a47
13753c1b40b1c
14375dd4cb859
151b871447c0a
hexedc6b72857

1021241141335 has 4 divisors (see below), whose sum is σ = 1225489369608. Its totient is φ = 816992913064.

The previous prime is 1021241141317. The next prime is 1021241141363. The reversal of 1021241141335 is 5331411421201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1021241141335 - 217 = 1021241010263 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102124114129 + ... + 102124114138.

It is an arithmetic number, because the mean of its divisors is an integer number (306372342402).

Almost surely, 21021241141335 is an apocalyptic number.

1021241141335 is a deficient number, since it is larger than the sum of its proper divisors (204248228273).

1021241141335 is an equidigital number, since it uses as much as digits as its factorization.

1021241141335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204248228272.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 1021241141335 its reverse (5331411421201), we get a palindrome (6352652562536).

The spelling of 1021241141335 in words is "one trillion, twenty-one billion, two hundred forty-one million, one hundred forty-one thousand, three hundred thirty-five".

Divisors: 1 5 204248228267 1021241141335