Base | Representation |
---|---|
bin | 101111100011100010… |
… | …1011010000001011111 |
3 | 100202121012221112200110 |
4 | 1133013011122001133 |
5 | 3133122312043403 |
6 | 114525410501103 |
7 | 10243510330434 |
oct | 1370705320137 |
9 | 322535845613 |
10 | 102124331103 |
11 | 3a346582543 |
12 | 17961294793 |
13 | 98269691b2 |
14 | 4d2b241b8b |
15 | 29ca9ab103 |
hex | 17c715a05f |
102124331103 has 4 divisors (see below), whose sum is σ = 136165774808. Its totient is φ = 68082887400.
The previous prime is 102124331093. The next prime is 102124331189. The reversal of 102124331103 is 301133421201.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 102124331103 - 24 = 102124331087 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 102124331103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102124331203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17020721848 + ... + 17020721853.
It is an arithmetic number, because the mean of its divisors is an integer number (34041443702).
Almost surely, 2102124331103 is an apocalyptic number.
102124331103 is a deficient number, since it is larger than the sum of its proper divisors (34041443705).
102124331103 is an equidigital number, since it uses as much as digits as its factorization.
102124331103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34041443704.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 102124331103 its reverse (301133421201), we get a palindrome (403257752304).
The spelling of 102124331103 in words is "one hundred two billion, one hundred twenty-four million, three hundred thirty-one thousand, one hundred three".
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