10213003043301 has 4 divisors (see below), whose sum is σ = 13617337391072. Its totient is φ = 6808668695532.

The previous prime is 10213003043279. The next prime is 10213003043401. The reversal of 10213003043301 is 10334030031201.

10213003043301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10213003043301 - 2²⁶ = 10212935934437 is a prime.

It is a super-4 number, since 4×10213003043301⁴ (a number of 53 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10213003043401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1702167173881 + ... + 1702167173886.

It is an arithmetic number, because the mean of its divisors is an integer number (3404334347768).

Almost surely, 2^{10213003043301} is an apocalyptic number.

It is an amenable number.

10213003043301 is a deficient number, since it is larger than the sum of its proper divisors (3404334347771).

10213003043301 is an equidigital number, since it uses as much as digits as its factorization.

10213003043301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3404334347770.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 10213003043301 its reverse (10334030031201), we get a palindrome (20547033074502).

The spelling of 10213003043301 in words is "ten trillion, two hundred thirteen billion, three million, forty-three thousand, three hundred one".