10213111320013 has 4 divisors (see below), whose sum is σ = 11672127222880. Its totient is φ = 8754095417148.

The previous prime is 10213111320011. The next prime is 10213111320053. The reversal of 10213111320013 is 31002311131201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10213111320013 - 2¹ = 10213111320011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10213111320011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 729507951423 + ... + 729507951436.

It is an arithmetic number, because the mean of its divisors is an integer number (2918031805720).

Almost surely, 2^{10213111320013} is an apocalyptic number.

It is an amenable number.

10213111320013 is a deficient number, since it is larger than the sum of its proper divisors (1459015902867).

10213111320013 is an equidigital number, since it uses as much as digits as its factorization.

10213111320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1459015902866.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 10213111320013 its reverse (31002311131201), we get a palindrome (41215422451214).

The spelling of 10213111320013 in words is "ten trillion, two hundred thirteen billion, one hundred eleven million, three hundred twenty thousand, thirteen".