Base | Representation |
---|---|
bin | 11101101110010110001… |
… | …00100000001101110111 |
3 | 10121122012010212012102211 |
4 | 32313023010200031313 |
5 | 113213122414021120 |
6 | 2101104003514251 |
7 | 133534055334022 |
oct | 16671304401567 |
9 | 3548163765384 |
10 | 1021314204535 |
11 | 364156274269 |
12 | 145b30088987 |
13 | 754040129a1 |
14 | 376090aa1b9 |
15 | 1b877a7b25a |
hex | edcb120377 |
1021314204535 has 4 divisors (see below), whose sum is σ = 1225577045448. Its totient is φ = 817051363624.
The previous prime is 1021314204517. The next prime is 1021314204577. The reversal of 1021314204535 is 5354024131201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1021314204535 - 211 = 1021314202487 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1021314204497 and 1021314204506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102131420449 + ... + 102131420458.
It is an arithmetic number, because the mean of its divisors is an integer number (306394261362).
Almost surely, 21021314204535 is an apocalyptic number.
1021314204535 is a deficient number, since it is larger than the sum of its proper divisors (204262840913).
1021314204535 is an equidigital number, since it uses as much as digits as its factorization.
1021314204535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 204262840912.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1021314204535 its reverse (5354024131201), we get a palindrome (6375338335736).
The spelling of 1021314204535 in words is "one trillion, twenty-one billion, three hundred fourteen million, two hundred four thousand, five hundred thirty-five".
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