Base | Representation |
---|---|
bin | 10011000001100000… |
… | …10110000001010001 |
3 | 222100202222100120110 |
4 | 21200300112001101 |
5 | 131404041023213 |
6 | 4405240431533 |
7 | 511043640603 |
oct | 114060260121 |
9 | 28322870513 |
10 | 10213220433 |
11 | 4371107749 |
12 | 1b904785a9 |
13 | c69c23100 |
14 | 6cc5c7173 |
15 | 3eb9795c3 |
hex | 260c16051 |
10213220433 has 24 divisors (see below), whose sum is σ = 14793971808. Its totient is φ = 6264490752.
The previous prime is 10213220431. The next prime is 10213220453. The reversal of 10213220433 is 33402231201.
It is not a de Polignac number, because 10213220433 - 21 = 10213220431 is a prime.
It is a super-2 number, since 2×102132204332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10213220431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 122841 + ... + 188457.
It is an arithmetic number, because the mean of its divisors is an integer number (616415492).
Almost surely, 210213220433 is an apocalyptic number.
10213220433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10213220433 is a deficient number, since it is larger than the sum of its proper divisors (4580751375).
10213220433 is a wasteful number, since it uses less digits than its factorization.
10213220433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65953 (or 65940 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 10213220433 its reverse (33402231201), we get a palindrome (43615451634).
The spelling of 10213220433 in words is "ten billion, two hundred thirteen million, two hundred twenty thousand, four hundred thirty-three".
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