Base | Representation |
---|---|
bin | 1001010010011111001110… |
… | …1101011101001100000011 |
3 | 1100011101010021122111021110 |
4 | 2110213303231131030003 |
5 | 2314313141331321430 |
6 | 33415520303054403 |
7 | 2102611155655665 |
oct | 224476355351403 |
9 | 40141107574243 |
10 | 10213226042115 |
11 | 328844a92a438 |
12 | 118b4848a1403 |
13 | 591145621005 |
14 | 2744739ba535 |
15 | 12aa095b97b0 |
hex | 949f3b5d303 |
10213226042115 has 16 divisors (see below), whose sum is σ = 16341768642816. Its totient is φ = 5446851564000.
The previous prime is 10213226042081. The next prime is 10213226042213. The reversal of 10213226042115 is 51124062231201.
It is not a de Polignac number, because 10213226042115 - 211 = 10213226040067 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12227581 + ... + 13036110.
It is an arithmetic number, because the mean of its divisors is an integer number (1021360540176).
Almost surely, 210213226042115 is an apocalyptic number.
10213226042115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10213226042115 is a deficient number, since it is larger than the sum of its proper divisors (6128542600701).
10213226042115 is a wasteful number, since it uses less digits than its factorization.
10213226042115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25290650.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 10213226042115 its reverse (51124062231201), we get a palindrome (61337288273316).
The spelling of 10213226042115 in words is "ten trillion, two hundred thirteen billion, two hundred twenty-six million, forty-two thousand, one hundred fifteen".
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