Base | Representation |
---|---|
bin | 1001010010011111010000… |
… | …1101010101111110111011 |
3 | 1100011101010212101011210121 |
4 | 2110213310031111332323 |
5 | 2314313201001314321 |
6 | 33415521202154111 |
7 | 2102611320012352 |
oct | 224476415257673 |
9 | 40141125334717 |
10 | 10213234401211 |
11 | 3288454619786 |
12 | 118b487652937 |
13 | 591147289a1a |
14 | 274474b54999 |
15 | 12aa0a1bb441 |
hex | 949f4355fbb |
10213234401211 has 4 divisors (see below), whose sum is σ = 10380664473424. Its totient is φ = 10045804329000.
The previous prime is 10213234401143. The next prime is 10213234401221. The reversal of 10213234401211 is 11210443231201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10213234401211 - 211 = 10213234399163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10213234401221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83715036015 + ... + 83715036136.
It is an arithmetic number, because the mean of its divisors is an integer number (2595166118356).
Almost surely, 210213234401211 is an apocalyptic number.
10213234401211 is a deficient number, since it is larger than the sum of its proper divisors (167430072213).
10213234401211 is an equidigital number, since it uses as much as digits as its factorization.
10213234401211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 167430072212.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 10213234401211 its reverse (11210443231201), we get a palindrome (21423677632412).
The spelling of 10213234401211 in words is "ten trillion, two hundred thirteen billion, two hundred thirty-four million, four hundred one thousand, two hundred eleven".
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