10213342330333 has 4 divisors (see below), whose sum is σ = 10328098985820. Its totient is φ = 10098585674848.

The previous prime is 10213342330319. The next prime is 10213342330349. The reversal of 10213342330333 is 33303324331201.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3444301709689 + 6769040620644 = 1855883^2 + 2601738^2 .

It is a cyclic number.

It is not a de Polignac number, because 10213342330333 - 2¹⁷ = 10213342199261 is a prime.

It is a super-3 number, since 3×10213342330333³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10213342330295 and 10213342330304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10213342334333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57378327610 + ... + 57378327787.

It is an arithmetic number, because the mean of its divisors is an integer number (2582024746455).

Almost surely, 2^{10213342330333} is an apocalyptic number.

It is an amenable number.

10213342330333 is a deficient number, since it is larger than the sum of its proper divisors (114756655487).

10213342330333 is an equidigital number, since it uses as much as digits as its factorization.

10213342330333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114756655486.

The product of its (nonzero) digits is 34992, while the sum is 31.

Adding to 10213342330333 its reverse (33303324331201), we get a palindrome (43516666661534).

The spelling of 10213342330333 in words is "ten trillion, two hundred thirteen billion, three hundred forty-two million, three hundred thirty thousand, three hundred thirty-three".