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1021351305113 = 8312305437411
BaseRepresentation
bin11101101110011010100…
…10000001111110011001
310121122021201200002212022
432313031102001332121
5113213211413230423
62101111411024225
7133535015564666
oct16671522017631
93548251602768
101021351305113
113641752044a7
12145b4059b075
137540b9028a9
143760dda6a6d
151b87ae58dc8
hexedcd481f99

1021351305113 has 4 divisors (see below), whose sum is σ = 1033656742608. Its totient is φ = 1009045867620.

The previous prime is 1021351305053. The next prime is 1021351305133. The reversal of 1021351305113 is 3115031531201.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1021351305113 - 226 = 1021284196249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1021351305133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6152718623 + ... + 6152718788.

It is an arithmetic number, because the mean of its divisors is an integer number (258414185652).

Almost surely, 21021351305113 is an apocalyptic number.

It is an amenable number.

1021351305113 is a deficient number, since it is larger than the sum of its proper divisors (12305437495).

1021351305113 is an equidigital number, since it uses as much as digits as its factorization.

1021351305113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12305437494.

The product of its (nonzero) digits is 1350, while the sum is 26.

Adding to 1021351305113 its reverse (3115031531201), we get a palindrome (4136382836314).

The spelling of 1021351305113 in words is "one trillion, twenty-one billion, three hundred fifty-one million, three hundred five thousand, one hundred thirteen".

Divisors: 1 83 12305437411 1021351305113