102138433 has 4 divisors (see below), whose sum is σ = 107514160. Its totient is φ = 96762708.

The previous prime is 102138401. The next prime is 102138437. The reversal of 102138433 is 334831201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334831201 = 17 ⋅19695953.

It is a cyclic number.

It is not a de Polignac number, because 102138433 - 2⁵ = 102138401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102138398 and 102138407.

It is not an unprimeable number, because it can be changed into a prime (102138437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2687835 + ... + 2687872.

It is an arithmetic number, because the mean of its divisors is an integer number (26878540).

Almost surely, 2^102138433 is an apocalyptic number.

It is an amenable number.

102138433 is a deficient number, since it is larger than the sum of its proper divisors (5375727).

102138433 is an equidigital number, since it uses as much as digits as its factorization.

102138433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5375726.

The product of its (nonzero) digits is 1728, while the sum is 25.

The square root of 102138433 is about 10106.3560693259. The cubic root of 102138433 is about 467.4441512969. Note that the first 3 decimals are identical.

Adding to 102138433 its reverse (334831201), we get a palindrome (436969634).

The spelling of 102138433 in words is "one hundred two million, one hundred thirty-eight thousand, four hundred thirty-three".