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102144331411 = 176008490083
BaseRepresentation
bin101111100100001000…
…1101100111010010011
3100202122121120122221121
41133020101230322103
53133142422101121
6114531403303111
710244142330403
oct1371021547223
9322577518847
10102144331411
113a3568a3021
1217967b1aa97
13982ab4c7b5
144d2db6a803
1529cc60c141
hex17c846ce93

102144331411 has 4 divisors (see below), whose sum is σ = 108152821512. Its totient is φ = 96135841312.

The previous prime is 102144331369. The next prime is 102144331433. The reversal of 102144331411 is 114133441201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 102144331411 - 211 = 102144329363 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102144331511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3004245025 + ... + 3004245058.

It is an arithmetic number, because the mean of its divisors is an integer number (27038205378).

Almost surely, 2102144331411 is an apocalyptic number.

102144331411 is a deficient number, since it is larger than the sum of its proper divisors (6008490101).

102144331411 is an equidigital number, since it uses as much as digits as its factorization.

102144331411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6008490100.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 102144331411 its reverse (114133441201), we get a palindrome (216277772612).

The spelling of 102144331411 in words is "one hundred two billion, one hundred forty-four million, three hundred thirty-one thousand, four hundred eleven".

Divisors: 1 17 6008490083 102144331411