Base | Representation |
---|---|
bin | 11101101110100110101… |
… | …11011111101111011111 |
3 | 10121122112211210010011111 |
4 | 32313103113133233133 |
5 | 113213414032313210 |
6 | 2101125455202451 |
7 | 133540365436543 |
oct | 16672327375737 |
9 | 3548484703144 |
10 | 1021453401055 |
11 | 3642178a770a |
12 | 145b6a816427 |
13 | 75426acb3a9 |
14 | 3761d781a23 |
15 | 1b884dc488a |
hex | edd35dfbdf |
1021453401055 has 16 divisors (see below), whose sum is σ = 1233609198624. Its totient is φ = 811934622720.
The previous prime is 1021453401053. The next prime is 1021453401113. The reversal of 1021453401055 is 5501043541201.
It is not a de Polignac number, because 1021453401055 - 21 = 1021453401053 is a prime.
It is a super-2 number, since 2×10214534010552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1021453401053) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 422934 + ... + 1490563.
It is an arithmetic number, because the mean of its divisors is an integer number (77100574914).
Almost surely, 21021453401055 is an apocalyptic number.
1021453401055 is a deficient number, since it is larger than the sum of its proper divisors (212155797569).
1021453401055 is a wasteful number, since it uses less digits than its factorization.
1021453401055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1914186.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 1021453401055 its reverse (5501043541201), we get a palindrome (6522496942256).
The spelling of 1021453401055 in words is "one trillion, twenty-one billion, four hundred fifty-three million, four hundred one thousand, fifty-five".
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